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900=0.15x^2
We move all terms to the left:
900-(0.15x^2)=0
We get rid of parentheses
-0.15x^2+900=0
a = -0.15; b = 0; c = +900;
Δ = b2-4ac
Δ = 02-4·(-0.15)·900
Δ = 540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{540}=\sqrt{36*15}=\sqrt{36}*\sqrt{15}=6\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{15}}{2*-0.15}=\frac{0-6\sqrt{15}}{-0.3} =-\frac{6\sqrt{15}}{-0.3} =-\frac{\sqrt{15}}{-0.05} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{15}}{2*-0.15}=\frac{0+6\sqrt{15}}{-0.3} =\frac{6\sqrt{15}}{-0.3} =\frac{\sqrt{15}}{-0.05} $
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